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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If ∑r=1nr4=f(n)\sum_{r=1}^n r^4=f(n), then ∑r=1n(2r−1)4\sum_{r=1}^n(2 r-1)^4 is equal to
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Correct option: A
f(2n)−16f(n)f(2 n)-16 f(n)
Option A (f(2n)−16f(n)f(2 n)-16 f(n)) is correct because the sum of (2r-1)4 from r=1 to n can be expressed as the difference between the sum of r4 from r=1 to 2n and 16 times the sum of r4 from r=1 to n.

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