JEE MATHEMATICS MCQ: DOT PRODUCT OF VECTORS

1 Easy

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Application +4 | -1

A velocity

\frac{1}{4} \mathrm{~m} / \mathrm{s}

is resolved into two components along

O A

and

O B

making angles

30^{\circ}

and

45^{\circ}

respectively with the given velocity. Then the component along

O B

View answer and explanation

Correct option: A

\frac{1}{8}(\sqrt{6}-\sqrt{2}) \mathrm{m} / \mathrm{s}

Option A (

\frac{1}{8}(\sqrt{6}-\sqrt{2}) \mathrm{~m} / \mathrm{s}

) is correct because it is the component of the velocity along OB, calculated using the sine rule for resolving velocities.

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