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NEET • PHYSICS • WAVES

Waves practice · Mixed difficulty

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Showing 1-30 of 215 questions
1 Medium
1 of 215
Application +4 | -1
A 1000  Hz1000\,\,Hz sound wave in air strikes the surface of a lake and penetrates into water. If speed of sound in water is 1500  ms−11500\,\,\mathrm{m}{\mathrm{s}^{ - 1}}, the frequency and wavelength of waves in water are
View answer and explanation
Correct option: B
1000  Hz,1.5  m1000\,\,\mathrm{ }Hz,\mathrm{ }1.5\,\,m
Option B (1000 Hz, 1.5 m) is correct because the frequency remains the same when a wave travels from one medium to another, and the wavelength changes according to the change in speed.
2 Medium
2 of 215
Understanding +4 | -1
The equation for spherical progressive wave is (where rr is the distance from the source)
View answer and explanation
Correct option: D
y=ar  sin⁡(ωt−kx)y = \frac{a}{r}\,\,\sin \left( {\omega t - kx} \right)
Option D (y=ar  sin⁡(ωt−kx)y = \frac{a}{r}\,\,\sin \left( {\omega t - kx} \right)) is correct because the amplitude of a spherical wave decreases inversely with the distance from the source.
3 Medium
3 of 215
Application +4 | -1
One metre long tube, closed at both ends, is lying horizontally. A mercury column of length 0.1m is filled in its middle and in rest two parts air is filled at atmospheric pressure. When tube is turned to vertical position, then displacement of mercury will be (standard pressure = 0.76 m of Hg)
View answer and explanation
Correct option: C
0.029 m
Option C (0.029 m) is correct because it is calculated by applying Boyle's law to the air columns and considering the pressure difference due to the mercury column.
4 Medium
4 of 215
Understanding +4 | -1
A tuning fork produces waves in a medium. If the temperature of the medium changes, then which of the following will change
View answer and explanation
Correct option: C
Wavelength
Option C (Wavelength) is correct because the speed of sound changes with temperature, and since frequency remains constant, the wavelength must change.
5 Medium
5 of 215
Understanding +4 | -1
In a stationary wave all the particles
View answer and explanation
Correct option: B
In the region between two nodes vibrate in same phase
Option B (In the region between two nodes vibrate in same phase) is correct because in a stationary wave, particles between two consecutive nodes vibrate in the same phase, while particles in adjacent segments vibrate in opposite phases.
6 Easy
6 of 215
Application +4 | -1
A SONAR system fixed in a submarine operates at a frequency 40.0kHz40.0 \mathrm{kHz}. An enemy submarine moves towards the SONAR with a speed of 360 km/h360 \mathrm{~km} / \mathrm{h}. What is the frequency of sound reflected by a submarine? Take the speed of sound in water to be 1450 m/s1450 \mathrm{~m} / \mathrm{s}.
View answer and explanation
Correct option: A
45.93×103  45.93 \times {10^3}\,\,
Option A (45.93×103  45.93 \times {10^3}\,\,) is correct because it is the frequency calculated using the Doppler effect formula for both the submarine approaching and reflecting the sound.
7 Hard
7 of 215
Application +4 | -1
A train moving at a speed of 220  ms−1220\,\,m{s^{ - 1}} towards a stationary object, emits a sound of frequency 1000 Hz. Some of the sound reaching the object gets reflected back to the train as echo. The frequency of the echo as detected by the driver of the train is {speed of sound in air is 330  ms−1330\,\,m{s^{ - 1}} ]
View answer and explanation
Correct option: C
5000 Hz
Option C (5000 Hz) is correct because it is the frequency of the echo detected by the train driver, calculated using the Doppler effect twice.
8 Medium
8 of 215
Analyzing +4 | -1
Two tuning forks AA and BB vibrating simultaneously produce 55 beats. Frequency of BB is 512512. It is seen that if one arm of AA is filled, then the number of beats increases. Frequency of AA will be
View answer and explanation
Correct option: C
517517
Option C (517517) is correct because filing arm A increases its frequency, and since the beat frequency increases, the original frequency of A must have been higher than B.
9 Medium
9 of 215
Understanding +4 | -1
A uniform heavy string of mass M hangs vertically from a rigid ceiling. A transverse wave is sent from its free end towards fixed end. As the wave moves upward
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Correct option: B
Its speed and wavelength increases
Option B (Its speed and wavelength increases) is correct because as the wave moves upward, the tension in the string increases, leading to an increase in both speed and wavelength.
10 Medium
10 of 215
Understanding +4 | -1
Doppler effect of sound depends on
View answer and explanation
Correct option: C
Relative velocity between source and listener
Option C (Relative velocity between source and listener) is correct because the Doppler effect is directly dependent on the relative velocity between the source and the observer.
11 Medium
11 of 215
Application +4 | -1
A cylindrical tube containing air is open at both ends. If the shortest length of the tube for resonance with a given fork is 20  cm20\,\,cm, the next shortest length for resonance with the same fork will be
View answer and explanation
Correct option: B
40cm40\mathrm{ }cm
Option B (40cm40\mathrm{ }cm) is correct because the next shortest length for resonance in an open tube is twice the shortest length.
12 Medium
12 of 215
Application +4 | -1
The frequency of the sinusoidal wave
y=0.40   cos⁡[2000t+0.80x]y = 0.40\,\,\,\cos \left[ {2000t + 0.80x} \right] would be
View answer and explanation
Correct option: D
1000πHz\frac{{1000}}{\pi }Hz
Option D (1000πHz\frac{{1000}}{\pi }Hz) is correct because the frequency is calculated from the coefficient of time in the given sinusoidal wave equation.
13 Medium
13 of 215
Application +4 | -1
Three sources of equal intensities with frequencies 400,  401   and   402  vib/s400,\,\,401\,\,\,and\,\,\,402\,\,vib/s are sounded together. The number of beats/s is
View answer and explanation
Correct option: C
22
Option C (2) is correct because the number of beats is determined by the maximum difference between the frequencies.
14 Medium
14 of 215
Analyzing +4 | -1
Three successive resonance frequencies in an organ pipe are 1310,1834 and 2358Hz2358 \mathrm{Hz}. The frequency of 1st 1^{\text {st }} overtone (in Hz\mathrm{Hz} ) is (velocity of sound in air is 340m/s340 \mathrm{m} / \mathrm{s} )
View answer and explanation
Correct option: B
786
Option B (786) is correct because the difference between successive resonance frequencies is constant in an organ pipe, allowing us to determine the fundamental frequency and then the first overtone.
15 Medium
15 of 215
Understanding +4 | -1
A sonometer wire is vibrating in the second overtone. In the wire there are
View answer and explanation
Correct option: C
Four nodes and three antinodes
Option D (Three nodes and three antinodes) is correct because the second overtone corresponds to the third harmonic, which has three antinodes and four nodes.
16 Easy
16 of 215
Application +4 | -1
If speed of sound in air is 330 m/s330 \mathrm{~m} / \mathrm{s} then find the number of tones present in an open organ pipe of length 1 m1 \mathrm{~m} whose frequency if ≤1000\leq 1000.
View answer and explanation
Correct option: A
6
Option A (6) is correct because the number of tones can be found by calculating the harmonics that fall below 1000 Hz.
17 Hard
17 of 215
Analyzing +4 | -1
Equation of progressive wave is:

y=asin⁡2π4cos⁡2π4sin⁡(ωt−kx±ϕ)y=a \sin ^2 \frac{\pi}{4} \cos ^2 \frac{\pi}{4} \sin (\omega t-k x \pm \phi)

where symbols having their usual meanings then for given wave equation:

(a) Amplitude =asin⁡2π4cos⁡2π4=a \sin ^2 \frac{\pi}{4} \cos ^2 \frac{\pi}{4}

(b) Wavelength =2πK=\frac{2 \pi}{{K}}

(c) Unit of y=y= unit of amplitude, unit of wavelength == unit of xx

(d) Frequency =ω2π=\frac{\omega}{2 \pi}
View answer and explanation
Correct option: C
a, b, c, d are correct
Option C (a, b, c, d are correct) is correct because all the statements about the amplitude, wavelength, units, and frequency are accurate based on the given wave equation.
18 Easy
18 of 215
Understanding +4 | -1
Statement I Waves on a string can be longitudinal in nature.

Statement II The string cannot be compressed or rarified.
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Correct option: D
Statement I is false, Statement II is true
Option D is correct because waves on a string are transverse, and the string cannot be compressed or rarefied.
19 Medium
19 of 215
Remembering +4 | -1
The pitch of a sound wave is related to its
View answer and explanation
Correct option: A
Frequency
Option A (Frequency) is correct because the pitch of a sound wave is directly determined by its frequency.
20 Medium
20 of 215
Remembering +4 | -1
Which of the following is the longitudinal wave
View answer and explanation
Correct option: A
Sound waves
Option A (Sound waves) is correct because sound waves are characterized by the compression and rarefaction of the medium, making them longitudinal.
21 Medium
21 of 215
Analyzing +4 | -1
The wavelength of two notes in air are 36195m\frac{{36}}{{195}}m and 36193m\frac{{36}}{{193}}m each note produces 1010 beats per second separately with a third note of fixed frequency. The velocity of sound in air in m/sm/s is
View answer and explanation
Correct option: D
360360
Option D (360360) is correct because it is calculated by finding the frequencies from the wavelengths and then using the beat frequency to determine the velocity of sound.
22 Medium
22 of 215
Remembering +4 | -1
Of the following, the equation of plane progressive wave is
View answer and explanation
Correct option: B
y=r  sin⁡(ωt−kx)y = r\,\,\sin \left( {\omega t - kx} \right)
Option B (y=r sin⁡(ωt−kx)y = r\,\sin (\omega t - kx)) is correct because it represents the general equation of a plane progressive wave.
23 Medium
23 of 215
Remembering +4 | -1
A device used for investigating the vibration of a fixed string of wire is
View answer and explanation
Correct option: A
Sonometer
Option A (Sonometer) is correct because a sonometer is specifically designed to investigate the vibration of a fixed string or wire.
24 Medium
24 of 215
Analyzing +4 | -1
Equations of a stationary wave and a travelling wave are y1=a  sin⁡  kx  cos⁡  ωt{y_1} = a\,\,\sin \,\,kx\,\,\cos \,\,\omega t and y2=a  sin⁡(ωt−kx){y_2} = a\,\,\sin \left( {\omega t - kx} \right). The phase difference between two points x1=π3k{x_1} = \frac{\pi }{{3k}} and x2=3π2k{x_2} = \frac{{3\pi }}{{2k}}are ϕ1{\phi _1} and ϕ2{\phi _2} respectively for the two waves. The ratio ϕ1/ϕ2{\phi _1}/{\phi _2} is
View answer and explanation
Correct option: D
6/76/7
Option D (6/76/7) is correct because it represents the ratio of the phase differences calculated for the stationary and traveling waves at the given points.
25 Medium
25 of 215
Understanding +4 | -1
When we hear a sound, we can identify its source from
View answer and explanation
Correct option: D
Overtones present in the sound
Option D (Overtones present in the sound) is correct because the unique combination of overtones (harmonics) gives each sound source its characteristic timbre.
26 Easy
26 of 215
Understanding +4 | -1
Tube A has both ends open while tube B has one end closed, otherwise. They are identical the ratio of fundamental frequency of tube A and B is
View answer and explanation
Correct option: C
0.084027778
Option A (0.043055556) is incorrect. The correct ratio of fundamental frequencies is 2:1, so the ratio of A to B should be 2. The provided answer is not correct.
27 Easy
27 of 215
Application +4 | -1
What is the phase difference between two simple harmonic motions represented by

x1=Asin⁡(ωt+π6) and x2=Acos⁡ωt ? x_1=A \sin \left(\omega t+\frac{\pi}{6}\right) \text { and } x_2=A \cos \omega t \text { ? }
View answer and explanation
Correct option: B
π3\frac{\pi}{3}
Option B is correct because converting cosine to sine and finding the difference in phase angles gives pi/3.
28 Medium
28 of 215
Remembering +4 | -1
Maximum number of beats frequency heard by a human being is
View answer and explanation
Correct option: A
1010
Option A (1010) is correct because the maximum beat frequency a human can typically distinguish is around 10 Hz.
29 Easy
29 of 215
Understanding +4 | -1
The two waves of the same frequency moving in the same direction give rise to
View answer and explanation
Correct option: B
Interference
Option B (Interference) is correct because when two waves of the same frequency meet, they superpose to create interference.
30 Medium
30 of 215
Analyzing +4 | -1
Total number of independent harmonic waves in the resultant displacement equation given by
y=3sin⁡2t2sin⁡800ty=3 \sin ^2 \frac{t}{2} \sin 800 t
View answer and explanation
Correct option: A
3
Option A (3) is correct because the trigonometric identity transforms the equation into a sum of three harmonic waves with different frequencies.
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Key Takeaways

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