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NEET • PHYSICS • NUCLEI

Nuclei practice · Mixed difficulty

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Showing 1-30 of 210 questions
1 Medium
1 of 210
Application +4 | -1
The ratio of the nuclear radii of elements with mass numbers 216\mathrm{216} and 125\mathrm{125} is
View answer and explanation
Correct option: C
6:5\mathrm{6:5}
Option C (6:5) is correct because the nuclear radius is proportional to the cube root of the mass number.
2 Easy
2 of 210
Application +4 | -1
In a hypothetical fission reaction

92X236→56Y141+36Z92+3R{ }_{92} X^{236} \rightarrow{ }_{56} Y^{141}+{ }_{36} Z^{92}+3 R

The identity of emitted particles (R)({R}) is:
View answer and explanation
Correct option: C
Neutron
Option C (Neutron) is correct because in nuclear fission reactions, neutrons are often released as products. Checking mass and charge balance confirms this.
3 Medium
3 of 210
Application +4 | -1
The radius of the nucleus of the atom with A=216 is (take R0  =1.3fm{R_0}\; = \mathrm{ }1.3fm)
View answer and explanation
Correct option: B
7.8 fm
Option B (7.8 fm) is correct because it is calculated using the formula for nuclear radius, R=R0A1/3R = R_0 A^{1/3}, where A is the mass number and R0=1.3fmR_0 = 1.3 fm.
4 Medium
4 of 210
Understanding +4 | -1
The correct sequence of the increasing wavelength of the given radiation sources is
View answer and explanation
Correct option: B
Radioactive source, X-ray tube, sodium vapour lamp, crystal oscillator
Option B is correct because it presents the electromagnetic spectrum in the correct order of increasing wavelength, from radioactive sources (shortest wavelength) to crystal oscillators (longest wavelength).
5 Easy
5 of 210
Application +4 | -1
Which of the following nuclear fragments corresponding to nuclear fission between neutron (01n)\left({ }_0^1 \mathrm{n}\right) and uranium isotope (92235U)\left({ }_{92}^{235} \mathrm{U}\right) is correct:
View answer and explanation
Correct option: D
56144Ba+3689Kr+301n{ }_{56}^{144} \mathrm{Ba}+{ }_{36}^{89} \mathrm{Kr}+3_0^1 \mathrm{n}
Option D is correct because it accurately represents a possible fission reaction of uranium-235 with a neutron, conserving both mass number and atomic number.
6 Medium
6 of 210
Remembering +4 | -1
Which of the following has the mass closest in value to that of the positron
1  a.m.u=931  MeV1\,\,a.m.u = 931\,\,MeV
View answer and explanation
Correct option: B
Electron
Option B is correct because a positron is the antiparticle of an electron, and therefore has the same mass as an electron.
7 Medium
7 of 210
Understanding +4 | -1
The binding energy of nucleus is a measure of its
View answer and explanation
Correct option: D
Stability
Option D (Stability) is correct because the binding energy of a nucleus is a direct measure of how stable the nucleus is.
8 Medium
8 of 210
Analyzing +4 | -1
10 gm of a radioactive element is kept in a container. The element is β\beta-active. Then after one half-life:

(molar mass of the substance is 100 gm, Avogadro's number =6×1023=6 \times 10^{23} per mole)
View answer and explanation
Correct option: C
If all β\beta particles leave the container then the charge of the substance left is 4800 C
Option C is correct because after one half-life, half the radioactive material decays, and if all beta particles leave, the remaining substance will have a positive charge due to the loss of negative beta particles.
9 Medium
9 of 210
Remembering +4 | -1
Which shows radioactivity?
View answer and explanation
Correct option: C
Tritium
Option C (Tritium) is correct because Tritium, being an isotope of hydrogen with two neutrons, is radioactive.
10 Medium
10 of 210
Remembering +4 | -1
The density of uranium is of the order of
View answer and explanation
Correct option: A
1020  kgm−3{10^{20}}\,\,\mathrm{kg}{\mathrm{m}^{ - 3}}
The correct answer is not provided in the options. The density of nuclear matter is approximately 1017 kgm−3{10^{17}}\,\mathrm{kg}{\mathrm{m}^{ - 3}}.
11 Medium
11 of 210
Application +4 | -1
Determine the number of nuclei that will be decayed upto one average life of radioactive material? (N0{N_0} : Initial number of nuclei)
View answer and explanation
Correct option: B
N0(1−1e){N_0}\left( {1 - \frac{1}{e}} \right)
Option B is correct because the number of nuclei decayed up to one average life is given by the formula N0(1−e−t/τ)N_0(1 - e^{-t/\tau}), where τ\tau is the average life.
12 Medium
12 of 210
Remembering +4 | -1
The phenomena in which proton flips is
View answer and explanation
Correct option: A
Nuclear magnetic resonance
Option A (Nuclear magnetic resonance) is correct because it is the phenomenon where proton flips occur due to the absorption of radiofrequency radiation.
13 Medium
13 of 210
Understanding +4 | -1
Cadmium rods are used in a nuclear reactor for
View answer and explanation
Correct option: C
Absorbing neutrons
Option C (Absorbing neutrons) is correct because cadmium rods are used in nuclear reactors to absorb neutrons, thereby controlling the chain reaction and regulating the power level.
14 Hard
14 of 210
Application +4 | -1
The explosive in a hydrogen bomb is a mixture of 1H2,1H3{ }_1 {H}^2,{ }_1 {H}^3 and 3Li6{ }_3 {Li}^6 in some condensed form. The chain reaction is given by

3Li6+0n1⟶2He4+1H31H2+1H3⟶2He4+0n1\begin{aligned} & { }_3 {Li}^6+{ }_0 {n}^1 \longrightarrow{ }_2 {He}^4+{ }_1 {H}^3 \\ & { }_1 {H}^2+{ }_1 {H}^3 \longrightarrow{ }_2 {He}^4+{ }_0 {n}^1 \end{aligned}

During the explosion the energy released is approximately
[Given : M(Li)=6.01690 amu,M(1H2)=2.01471 amu{M}({Li})=6.01690\, {amu}, {M}\left({ }_1 {H}^2\right)=2.01471\, {amu}, M(2He4)=4.00388 amu{M}\left({ }_2 {He}^4\right)=4.00388 \,{amu}, and 1 amu=931.5 MeV1\, {amu}=931.5 \,{MeV}]
View answer and explanation
Correct option: A
22.22 MeV22.22 \,{MeV}
Option A (22.22 MeV22.22 \,{MeV}) is correct because it is the approximate energy released during the fusion reactions, calculated from the mass defect.
15 Easy
15 of 210
Application +4 | -1
82290X→αY→e+Z→β−P→e−Q{ }_{82}^{290} X \xrightarrow{\alpha} Y \xrightarrow{e^{+}} Z \xrightarrow{\beta^{-}} P \xrightarrow{e^{-}} Q

In the nuclear emission stated above, the mass number and atomic number of the product QQ respectively, are
View answer and explanation
Correct option: C
286,81286,81
Option C is correct because after one alpha emission, one positron emission, and one beta-minus emission, and one electron capture, the mass number decreases by 4 and the atomic number decreases by 1 overall.
16 Medium
16 of 210
Understanding +4 | -1
For a nucleus to be stable, the correct relation between neutron number NN and proton number ZZ is
View answer and explanation
Correct option: D
N≥ZN \ge Z
Option D (N≥ZN \ge Z) is correct because for stable nuclei, the number of neutrons is generally greater than or equal to the number of protons, especially for heavier nuclei.
17 Easy
17 of 210
Understanding +4 | -1
Assertion: For an element generally N≥Z(N=N \geq Z(N= number of neutrons, Z=Z= atomic number)
Reason: Neutrons always experience attractive nuclear force.
View answer and explanation
Correct option: B
If both Assertion and Reason are true, but Reason is not the correct explanation of Assertion
Option B (If both Assertion and Reason are true, but Reason is not the correct explanation of Assertion) is correct because both statements are factually correct, but the neutron's attractive force isn't the primary reason for the N >= Z trend.
18 Medium
18 of 210
Application +4 | -1
The nuclear radius of a nucleus with nucleon number 16 is 3×10  −153\mathrm{ } \times \mathrm{ }10{\;^{ - 15}} metre. Then the nuclear radius of a nucleus with nucleon number 128 is
View answer and explanation
Correct option: C
6×10  −15m6\mathrm{ } \times \mathrm{ }10{\;^{ - 15}}m
Option C (6×10  −15m6\mathrm{ } \times \mathrm{ }10{\;^{ - 15}}m) is correct because the nuclear radius is proportional to the cube root of the nucleon number.
19 Medium
19 of 210
Remembering +4 | -1
Mean life of neutron is about
View answer and explanation
Correct option: B
1000 seconds\begin{array}{llllllllllllllllllll} {\mathrm{1000 }\,\mathrm{seconds}} \end{array}
Option B (1000 seconds) is correct because the mean lifetime of a free neutron is approximately 1000 seconds.
20 Medium
20 of 210
Understanding +4 | -1
Pick out the unmatched pair from the following
View answer and explanation
Correct option: D
Safety rods – Carbon
Option D (Safety rods – Carbon) is the unmatched pair because safety rods in nuclear reactors are typically made of materials like cadmium or boron, which are strong neutron absorbers, not carbon.
21 Medium
21 of 210
Analyzing +4 | -1
Fpe{\mathbf{F}_{pe}} represents electrical force on proton due to electron and Fep{\mathbf{F}_{ep}} on electron due to proton in a hydrogen atom.Similarly Fpe{\mathbf{F}_{pe}} represents the gravitational force on proton due to electron and Fep{\mathbf{F}_{ep}} the corresponding force on electron due to proton. Which of the following is not true?
View answer and explanation
Correct option: D
FPe+F′ Pe=0{\mathbf{F}_{Pe}} + \mathbf{F'}{\,_{Pe}} = 0
Option D (FPe+F′ Pe=0{\mathbf{F}_{Pe}} + \mathbf{F'}{\,_{Pe}} = 0) is not true because the electric and gravitational forces between the proton and electron are not equal in magnitude.
22 Medium
22 of 210
Understanding +4 | -1
The binding energy per nucleon for the parent nucleus is E1{E_1} and that for the daughter nuclei is E2{E_2}. Then
View answer and explanation
Correct option: C
E2>E1{E_2} > {E_1}
Option C (E2>E1{E_2} > {E_1}) is correct because daughter nuclei are more stable and have higher binding energy per nucleon than the parent nucleus.
23 Medium
23 of 210
Application +4 | -1
The mass defect in particular nuclear reaction if 0.3  g\mathrm{0}\mathrm{.3}\,\,\mathrm{g}. The amount of energy liberated in kilowatt hour is (Velocity of light =3  ×  108  ms−1= 3\,\, \times \,\,{10^8}\,\,\mathrm{m}{\mathrm{s}^{ - 1}}
View answer and explanation
Correct option: D
7.5  ×  1067.5\,\, \times \,\,{10^6}
Option D (7.5 × 1067.5\, \times \,{10^6}) is correct because the energy liberated is calculated using E=mc2E=mc^2 and then converted to kilowatt-hours.
24 Easy
24 of 210
Understanding +4 | -1
Statement-1: The mass per nucleon in a hydrogen atom is the same as the in an oxygen atom.
Statement-2: The energy released during the formation of nuclei of different atoms from their constituent nuclei is different.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D (Statement-1 is false, Statement-2 is true) is correct because the mass per nucleon varies between hydrogen and oxygen, and the energy released during nuclei formation differs.
25 Easy
25 of 210
Application +4 | -1
What would be the possible no. of elements if in nature elements with principal quantum number n>4n>4 were not allowed?
View answer and explanation
Correct option: A
60
Option A is correct because the number of elements is determined by the number of possible electron configurations, which is limited by the principal quantum number n. When n > 4 is not allowed, we sum the number of elements for n=1 to n=4.
26 Easy
26 of 210
Analyzing +4 | -1
The graph of ln⁡(RR0)\ln \left(\frac{R}{R_0}\right) versus ln⁡A\ln A (R=(R= radius of a nucleus and A=A= its mass number) is:
View answer and explanation
Correct option: A
a straight line
Option A (a straight line) is correct because the radius of a nucleus is proportional to A(1/3), leading to a linear relationship between ln(R/R0) and ln(A).
27 Hard
27 of 210
Application +4 | -1
The half life of a radioactive substance is 20 minutes the time taken between 50% decay and 87.5% decay of the substance will be
View answer and explanation
Correct option: C
40 min
Option C (40 min) is correct because it is the time difference between the two decay percentages, calculated using the half-life concept.
28 Hard
28 of 210
Application +4 | -1
A radioactive sample disintegrates by 10%10 \% during one month. How much fraction will disintegrate in four months :-
View answer and explanation
Correct option: A
34.39%34.39 \%
Option A (34.39 %) is correct because it calculates the fraction disintegrated after four months, given a 10% disintegration in one month.
29 Easy
29 of 210
Understanding +4 | -1
Which of the following is more effective for producing nuclear reactions with nuclei compared to protons?
View answer and explanation
Correct option: A
neutrons
Option A (neutrons) is correct because neutrons, being electrically neutral, are not repelled by the positively charged nucleus, making them more effective at penetrating the nucleus and causing nuclear reactions.
30 Medium
30 of 210
Application +4 | -1
A nuclear transformation is denoted by X  (n,α)→37  LiX\,\,(n,\alpha ) \to {}_3^7\,\,\mathrm{Li}. Which of the following is the nucleus of element XX ?
View answer and explanation
Correct option: B
510B{}_5^{10}\mathrm{B}
Option B (510B{}_5^{10}\mathrm{B}) is correct because, in the nuclear transformation, the mass and atomic numbers must be conserved.
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