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NEET • PHYSICS • ATOMS

Atoms practice · Mixed difficulty

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Showing 1-30 of 130 questions
1 Medium
1 of 130
Analyzing +4 | -1
Which of the following statements are true regarding Bohr’s model of hydrogen atom

(I) Orbiting speed of electron decreases as it shifts to discrete orbits away from the nucleus

(II) Radii of allowed orbits of electron are proportional to the principal quantum number

(III) Frequency with which electrons orbit around the nucleus is discrete orbits is inversely proportional to the cube of principal quantum number

(IV) Binding force with which the electron is bound to the nucleus increases as it shifts to outer orbits

Select correct answer using the codes given below
View answer and explanation
Correct option: A
I and III
Option A (I and III) is correct because the orbiting speed decreases as the electron moves away from the nucleus, and the frequency is inversely proportional to the cube of the principal quantum number.
2 Medium
2 of 130
Application +4 | -1
A particle moving with a velocity of 1100th\frac{1}{{100}}\mathrm{th} of that of light will cross a nucleus on about
View answer and explanation
Correct option: D
10−20  s{10^{ - 20}}\,\,\mathrm{s}
Option D (10−20  s{10^{ - 20}}\,\,\mathrm{s}) is correct because it estimates the time it takes for a particle moving at 1/100th the speed of light to cross a nucleus, using the approximate size of a nucleus.
3 Easy
3 of 130
Application +4 | -1
A hydrogen atom is in ground state absorbs a photon of ultraviolet radiation of wavelength 50 nm50 \mathrm{~nm}. Assuming that the entire photon energy is taken up by electron with what KE will the electron be emitted.
View answer and explanation
Correct option: C
11.2 eV11.2 \mathrm{~eV}
Option C (11.2 eV) is correct because the kinetic energy of the emitted electron is the energy of the photon minus the ionization energy of hydrogen (13.6 eV).
4 Medium
4 of 130
Application +4 | -1
In a spectrum of hydrogen atom, the ratio of shortest wavelength in Lyman series to longest wavelength in Paschen series is
View answer and explanation
Correct option: D
7144\frac{7}{{144}}
Option D (7144\frac{7}{{144}}) is correct because the shortest wavelength in the Lyman series corresponds to the transition from n=∞\infty to n=1, and the longest wavelength in the Paschen series corresponds to the transition from n=4 to n=3. Using the Rydberg formula, the ratio can be calculated.
5 Medium
5 of 130
Application +4 | -1
When the wave of hydrogen atom comes from infinity into the first orbit then the value of wave number is
View answer and explanation
Correct option: A
109700  cm−1109700\,\,c{m^{ - 1}}
Option A (109700  cm−1109700\,\,c{m^{ - 1}}) is correct because it represents the Rydberg constant, which is the wave number when an electron transitions from infinity to the first orbit in a hydrogen atom.
6 Medium
6 of 130
Remembering +4 | -1
To explain his theory, Bohr used
View answer and explanation
Correct option: B
Conservation of angular momentum
Option B (Conservation of angular momentum) is correct because Bohr's model is based on the quantization of angular momentum.
7 Medium
7 of 130
Analyzing +4 | -1
Assertion (A): Between any two given energy levels, the number of absorption transitions is always less than or equal to the number of emission transitions.

Reason (R): Absorption transitions start from the lowest energy level only and may end at any higher energy level. But emission trasitions may start from any higher energy level and end at an energy level below it.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because the number of absorption transitions is limited by the number of atoms in the lowest energy level, while emission transitions can originate from multiple higher energy levels, and the reason correctly explains this.
8 Medium
8 of 130
Analyzing +4 | -1
Stopping potentials of 24,100,11024,100,110 and 115 kV115 \mathrm{~kV} are measured for photoelectrons emitted from a certain element when it is irradiated with monochromatic X{X}-rays. If this element is used as a target in an XX-ray tube, what will be the wavelength of KαK_\alpha line? Assume that photons have sufficient energy to excite electrons of all the energy levels. [hc=12.4×103 eV.A∘]\left[hc=12.4 \times 10^3 \,\mathrm{eV} . \mathop A\limits^ \circ\right]
View answer and explanation
Correct option: D
0.163A∘0.163 \mathop A\limits^ \circ
Option D (0.163A∘0.163 \mathop A\limits^\circ) is correct because it is calculated by finding the energy difference between the K and L shells from the given stopping potentials and then using that energy to find the wavelength of the KαK_\alpha line.
9 Medium
9 of 130
Understanding +4 | -1
For characteristic XX-ray of some material
View answer and explanation
Correct option: C
λ(Kγ)<λ(Kβ)<λ(Kα)\lambda \left( {{K_\gamma }} \right) < \lambda \left( {{K_\beta }} \right) < \lambda \left( {{K_\alpha }} \right)
Option D (λ(Mα)<λ(Lα)<λ(Kα)\lambda \left( {{M_\alpha }} \right) < \lambda \left( {{L_\alpha }} \right) < \lambda \left( {{K_\alpha }} \right)) is correct because the energy of the transitions increases as you move closer to the nucleus (K shell), and since energy and wavelength are inversely proportional, the wavelength decreases.
10 Medium
10 of 130
Analyzing +4 | -1
Statement-1: When hydrogen atom is raised from the ground state to an excited state the kinetic energy increases.
Statement-2: The velocity of electron in a quantum state is inversely proportional to the quantum number of the state.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D (Statement-1 is false, Statement-2 is true) is correct because when an electron is raised to an excited state, its kinetic energy decreases, and the velocity is inversely proportional to the quantum number.
11 Medium
11 of 130
Application +4 | -1
An elementary particle of mass mm and charge +e+ e is projected with velocity vv at a much more massive particle of charge Ze,Ze, where Z>0.Z > 0. What is the closest possible approach of the incident particle
View answer and explanation
Correct option: A
Ze22πε0mv2\frac{{Z{e^2}}}{{2\pi {\varepsilon _0}m{v^2}}}
Option A (Ze22πε0mv2)\frac{{Z{e^2}}}{{2\pi {\varepsilon _0}m{v^2}}}) is correct because it represents the distance of closest approach derived from equating the initial kinetic energy to the electrostatic potential energy at the closest point.
12 Medium
12 of 130
Remembering +4 | -1
In the Bohr’s hydrogen atom model, the radius of the stationary orbit is directly proportional to (n=n = principle quantum number)
View answer and explanation
Correct option: D
n2{n^2}
Option D (n2{n^2}) is correct because the radius of the stationary orbit in Bohr's model is directly proportional to the square of the principal quantum number.
13 Medium
13 of 130
Remembering +4 | -1
The most penetrating radiation out of the following is
View answer and explanation
Correct option: D
γ\gamma-rays
Option D (γ\gamma-rays) is correct because gamma rays have the highest penetrating power among the given options due to their high energy and lack of charge.
14 Medium
14 of 130
Application +4 | -1
What will be the angular momentum of an electron, if energy of this electron in HH-atom is −1.5  eV- 1.5\,\,eV (in JJ-ss)
View answer and explanation
Correct option: C
3.15  ×10−343.15\,\, \times {10^{ - 34}}
Option C (3.15×10−343.15 \times {10^{ - 34}}) is correct. The angular momentum is quantized and related to the energy level in a hydrogen atom.
15 Medium
15 of 130
Remembering +4 | -1
The spectral series of the hydrogen spectrum that lies in the ultraviolet region is the
View answer and explanation
Correct option: D
Lyman series
Option D (Lyman series) is correct because the Lyman series corresponds to transitions to the n=1 energy level, which results in ultraviolet photons.
16 Easy
16 of 130
Understanding +4 | -1
The energy of the characteristic X-ray photon in Coolidge tube comes from
View answer and explanation
Correct option: B
The kinetic energy of the free electrons of the target
Option D (The electronic transition of the target atom) is correct because characteristic X-ray photons are emitted when electrons transition between energy levels within the target atom.
17 Medium
17 of 130
Remembering +4 | -1
Particles used in the Rutherford's scattering experiment to deduce the structure of atoms
View answer and explanation
Correct option: A
Had atomic number 2 and were fully ionised
Option A (Had atomic number 2 and were fully ionised) is correct because Rutherford's scattering experiment used alpha particles, which are helium nuclei (atomic number 2) and are fully ionized (He2+^{2+}).
18 Medium
18 of 130
Remembering +4 | -1
Energy of electron in an orbit of HH-atom is
View answer and explanation
Correct option: B
Negative
Option B (Negative) is correct because the energy of an electron in an orbit of a Hydrogen atom is always negative, indicating a bound state.
19 Medium
19 of 130
Analyzing +4 | -1
A monochromatic light is incident on a hydrogen sample in ground state. Hydrogen atoms absorb a fraction of light and subsequently emit radiation of six different wavelengths. The frequency of incident light is x×1015 Hzx \times 10^{15} \mathrm{~Hz}. The value of xx is_____

(Given h=4.25×10−15eVsh=4.25 \times 10^{-15} \mathrm{eVs} )
View answer and explanation
Correct option: A
3
The value of x is 3 because the hydrogen atom emits six different wavelengths, indicating it transitioned to n=4, and we can calculate the frequency of the incident light using the energy difference between n=1 and n=4.
20 Easy
20 of 130
Analyzing +4 | -1
Assuming that all the transitions are possible, consider the optical spectrum 3800A∘3800 \mathop A\limits^ \circ to 7700A∘7700 \mathop A\limits^ \circ. No. of lines of hydrogen as compared to doubly ionized lithium will be:
View answer and explanation
Correct option: B
Smaller
Option B (Smaller) is correct because the number of spectral lines for hydrogen is smaller compared to doubly ionized lithium due to the higher nuclear charge in lithium, which shifts the wavelengths outside the given range.
21 Medium
21 of 130
Understanding +4 | -1
Which of the following is true for number of spectral lines in going from Lyman series to PP-fund series
View answer and explanation
Correct option: B
Decreases
Option B (Decreases) is correct because the number of spectral lines decreases as we move from the Lyman series to the P-fund series due to the decreasing number of possible transitions.
22 Easy
22 of 130
Understanding +4 | -1
Which of the following is not the property of cathode rays?
View answer and explanation
Correct option: B
It does not deflect in an electric field.
Option B (It does not deflect in an electric field) is correct because cathode rays are streams of electrons, which are negatively charged and therefore deflect in an electric field.
23 Medium
23 of 130
Remembering +4 | -1
In Raman effect, Stoke’s lines are spectral lines having
View answer and explanation
Correct option: D
Wavelength greater than that of the original line
Option D (E2>E1>E3E_2 > E_1 > E_3) is correct because KβK_\beta photons have higher energy than KαK_\alpha photons, and the energy of KαK_\alpha photons increases with atomic number.
24 Medium
24 of 130
Remembering +4 | -1
The voltage applied across an X-ray tube is nearly equal to
View answer and explanation
Correct option: D
10, 000 V
Option D (10, 000 V) is correct because the voltage applied across an X-ray tube is typically on the order of 10,000 volts to accelerate electrons to sufficient energies for X-ray production.
25 Easy
25 of 130
Understanding +4 | -1
Given below are two statements:

Statement 1: Most of the mass of the atom and all its positive charge are concentrated in a tiny nucleus and the electrons revolve around it, is Rutherford's model.

Statement II : An atom is a spherical cloud of positive charges with electrons embedded in it, is a special case of Rutherford's model.

In the light of the above statements, choose the most appropriate from the options given below
View answer and explanation
Correct option: C
Statement I is true but statement II is false
Option C (Statement I is true but statement II is false) is correct because Rutherford's model describes a nucleus with orbiting electrons, while the statement II describes Thomson's model.
26 Hard
26 of 130
Application +4 | -1
In the Bohr's model of hydrogen-like atom the force between the nucleus and the electron is modified as F=e24πε0(1r2+βr3)F=\frac{e^2}{4 \pi \varepsilon_0}\left(\frac{1}{r^2}+\frac{\beta}{r^3}\right), where β\beta is a constant. For this atom, the radius of the nnth orbit in terms of the Bohr's radius (a0=ε0h2mπe2)\left(a_0=\frac{\varepsilon_0 h^2}{m \pi e^2}\right) is
View answer and explanation
Correct option: C
rn=a0n2−βr_n=a_0 n^2-\beta
Option C (rn=a0n2−βr_n=a_0 n^2-\beta) is correct because it is derived from balancing the modified force with the centripetal force and quantizing the angular momentum.
27 Hard
27 of 130
Application +4 | -1
If an element with principal quantum number n>4{n}>4 were not allowed in nature, the number of possible elements would be :-
View answer and explanation
Correct option: A
60
Option A (60) is correct because the number of elements is determined by the number of electrons that can occupy the allowed energy levels (n=1, 2, 3, 4).
28 Easy
28 of 130
Application +4 | -1
According to Bohr's theory, the moment of momentum of an electron revolving in 4th4^\text{th} orbit of hydrogen atom is:
View answer and explanation
Correct option: C
2hπ2 \frac{{h}}{\pi}
Option C (2hπ2 \frac{{h}}{\pi}) is correct because the angular momentum is given by L=nh2πL = n\frac{h}{2\pi}, and for the 4th orbit, n=4.
29 Medium
29 of 130
Analyzing +4 | -1
A XX-ray tube is working at a potential difference of 20 kV20 \,\mathrm{kV}. The potential difference is decreased to 10 kV10 \,\mathrm{kV}. It is found that difference of the wavelength of Kα XK_\alpha \,{X}-ray and the most energetic continuous X{X}-ray becomes 4 times of the difference prior to the change of voltage. Find the atomic number of the target element.
View answer and explanation
Correct option: A
55
Option C (Assertion is true but reason is false) is correct because while electrons are held by Coulomb forces, the reason provided for atomic stability is an oversimplification.
30 Medium
30 of 130
Analyzing +4 | -1
In separate experiments, four different particles each start from far away with the same speed and impinge directly on a gold nucleus. The masses and charges of the particles are

particle 1: mass m0{m}_0, charge q0{q}_0

particle 2: mass 2 m02{~m}_0, charge 2q02{q}_0

particle 3: mass 2 m02{~m}_0, charge q0/2{q}_0 / 2

particle 4: mass m0/2{m}_0 / 2, charge 2q02{q}_0

Rank the particles according to the distance of closest approach to the gold nucleus, from smallest to largest.
View answer and explanation
Correct option: A
3, then 1 and 2 tie, then 4
Option A (3, then 1 and 2 tie, then 4) is correct because the distance of closest approach is inversely proportional to the charge and directly proportional to the mass.
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