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NEET • CHEMISTRY • STRUCTURE OF ATOM

Structure of atom practice · Mixed difficulty

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Showing 1-30 of 492 questions

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1 Easy
1 of 492
Understanding +4 | -1
Which of the following pairs have identical values of e/m?
View answer and explanation
Correct option: A
Deuterium and an α-particles
Option A (Deuterium and an α-particles) is correct because both have a charge-to-mass ratio of approximately 1/2.
2 Easy
2 of 492
Remembering +4 | -1
The correct de Broglie relationship is:
View answer and explanation
Correct option: B
λ=hmu\lambda = \frac{h}{{mu}}
Option B (λ=hmu\lambda = \frac{h}{{mu}}) is correct because it represents the correct de Broglie relationship between wavelength, Planck's constant, mass, and velocity.
3 Medium
3 of 492
Analyzing +4 | -1
Assertion: Unlike sound waves, electromagnetic waves do not require medium and can move in vacuum.

Reason: The oscillating electric and magnetic fields produced by oscillating charged particles are parallel to each other and both are perpendicular to the direction of propagation of the wave.
View answer and explanation
Correct option: C
If A is true but R is false
Option C is correct because while the assertion is true, the reason is false. Electromagnetic waves do not require a medium, but the electric and magnetic fields are perpendicular to each other, not parallel.
4 Medium
4 of 492
Analyzing +4 | -1
S-I: The px{p}_{{x}} orbital has maximum electron density along the y axis and its nodal plane is xz plane.

S-II : For a given atom, for all values of nn, the p{p}-orbitals have the same shape, but the overall size decreases as 'nn' increases.
View answer and explanation
Correct option: B
Both S-I and S-II are incorrect
Option B (Both S-I and S-II are incorrect) is correct because the px{p}_{{x}} orbital has maximum electron density along the x axis and the size of p-orbitals increases as n increases.
5 Medium
5 of 492
Remembering +4 | -1
S-I: Elements like Rb,Cs,Tl,In,GaRb, Cs, Tl, In, Ga and ScSc were discovered when their minerals were analysed by spectroscopic methods.

S-II: The element helium was discovered in the sun by spectroscopic method.
View answer and explanation
Correct option: A
Both S-I and S-II are correct
The correct answer is A (Both S-I and S-II are correct) because spectroscopic methods were indeed crucial in discovering elements like Rb, Cs, Tl, In, Ga, Sc, and Helium.
6 Medium
6 of 492
Analyzing +4 | -1
In which one of the following, the number of protons is greater than number of neutrons but number of protons is less than the number of electrons?
View answer and explanation
Correct option: D
OH−\mathrm{OH}^{-}
Option D is correct because in OH⁻, there are 9 protons, 8 neutrons (in Oxygen-16 isotope), and 10 electrons.
7 Hard
7 of 492
Understanding +4 | -1
The ionisation potential of singly ionised Helium ion is equivalent to
View answer and explanation
Correct option: A
K.E of first orbit
Option A (K.E of first orbit) is correct because the ionization potential is the energy required to remove an electron from the atom, which is equal to the kinetic energy of the electron in the first orbit.
8 Medium
8 of 492
Understanding +4 | -1
Which of the following electrons is most tightly bound by the nucleus
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Correct option: A
4p
Option A (4p) is correct because electrons in lower energy levels and with lower azimuthal quantum numbers are more tightly bound.
9 Easy
9 of 492
Analyzing +4 | -1
Statement (S): H-atom has only one electron in its orbit, but several spectral lines are noticed

Explanation (E): The H\mathrm{H}-spectra is observed in H2\mathrm{H}_2 gas
View answer and explanation
Correct option: C
Both S and E are correct and E is correct explanation of S
Option A (S is correct but E is wrong) is correct because while H-atom does exhibit multiple spectral lines, the H-spectra is observed in individual H atoms, not H2H_2 gas.
10 Hard
10 of 492
Understanding +4 | -1
Consider the following statements:

I. The attractive interactions of an electron increases with increase of positive charge (Ze)\left(Z_e\right) on the nucleus.

II. Due to the presence of electrons in the inner shells, the electrons in the outer shell will not experience the full positive charge of the nucleus (Ze)\left(Z_e\right).

III. The effect will be lowered due to the partial screening of positive charge on the nucleus by the inner shell electrons.

IV. The net positive charge experienced by the other electrons is known as effective nuclear charge (Zeff )\left(Z_{\text {eff }}\right).
The correct statements are
View answer and explanation
Correct option: D
All of the above
Option D is correct because all the statements accurately describe the concepts of attractive interactions, inner shell electron shielding, and effective nuclear charge.
11 Medium
11 of 492
Remembering +4 | -1
Which of the following relation correctly described all the lines in the hydrogen spectrum?
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Correct option: A
vˉ=1109677[1n12−1n22]cm−1\bar{v}=\frac{1}{109677}\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right] \mathrm{cm}^{-1}
The correct answer is B. The Rydberg formula correctly describes all the lines in the hydrogen spectrum.
12 Medium
12 of 492
Remembering +4 | -1
The number of nodal planes ‘d’ orbital has
View answer and explanation
Correct option: C
Two
Option C (Electrons show wave nature) is correct because Davisson and Germer's experiment demonstrated the wave-particle duality of electrons by observing diffraction patterns.
13 Hard
13 of 492
Understanding +4 | -1
In hydrogen atom, which energy level order is not correct:
View answer and explanation
Correct option: C
2  p>2s2\;p > 2s
Option C (2  p>2s2\;p > 2s) is the correct answer because in a hydrogen atom, the energy levels depend only on the principal quantum number (n), so 2s and 2p have the same energy.
14 Easy
14 of 492
Understanding +4 | -1
From the discharge tube experiment, it is concluded that:
View answer and explanation
Correct option: B
Matter contains electrons
Option B (Matter contains electrons) is correct because the discharge tube experiment led to the discovery of electrons, demonstrating that matter contains these negatively charged particles.
15 Medium
15 of 492
Application +4 | -1
A particle A moving with a certain velocity has the de-Broglie wavelength of 1 A°. For particle B with mass 25% of A and velocity 75% of A, calculate the de-Broglie wavelength
View answer and explanation
Correct option: B
5.33 A°
Option B (5.33 A°) is correct because it is calculated using the de Broglie wavelength formula, considering the changes in mass and velocity.
16 Hard
16 of 492
Analyzing +4 | -1
Hydrogen like atom with atomic no ' Z\mathrm{Z} ' is in a higher excited state of quantum no. ' nn '. This excited state can make a transition to the first excited state by successively emitting two photons of energies 20ev&28.3ev20 \mathrm{ev} \& 28.3 \mathrm{ev} respectively. Alternatively the atom from the same excited state can make transition to the 2nd 2^{\text {nd }} excited state by emitting photons of energies 8.0ev&10.13ev8.0 \mathrm{ev} \& 10.13 \mathrm{ev} respectively. Determine ' Z\mathrm{Z} '
View answer and explanation
Correct option: A
3
The correct answer is A (3). By equating the total energy difference in both transitions, we can solve for Z.
17 Easy
17 of 492
Analyzing +4 | -1
The compound in which cation is isoelectronic with anion is
View answer and explanation
Correct option: D
K2S{K_2}S
Option D (K2S{K_2}S) is correct because both K+K^+ and S2−S^{2-} have the same number of electrons as Argon, making them isoelectronic.
18 Easy
18 of 492
Remembering +4 | -1
The electron possesses wave properties was shown experimentally by:
View answer and explanation
Correct option: C
Davission and germer
Option C is correct because Davisson and Germer experimentally demonstrated the wave nature of electrons through electron diffraction.
19 Hard
19 of 492
Understanding +4 | -1
Which of the following statements are correct?

(i) The second period (n=2)(n=2) starts with lithium and third electron enters the 2s2 s orbital. The next element, beryllium has four electrons and has the electronic configuration 1s22s21 s^2 2 s^2. From the next element boron, the 2p2 p orbitals are filled with electrons when the L\mathrm{L} shell is completed at neon (2s22p6)\left(2 s^2 2 p^6\right). Thus there are 8 elements in the second period.

(ii) Successive filling of 3s3 s and 3p3 p orbitals gives rise to the third period of 8 elements from sodium to argon.

(iii) The fourth period (n=4)(n=4) starts at potassium and the added electron fill up the first 4s4 s and 4p4 p orbitals than 3d3 d orbital is filled.

(iv) Fifth period begins with rubidium with the filling of 5 s5 \mathrm{~s} orbital and ends at xenon with the filling up of the 5p5 p orbital.
View answer and explanation
Correct option: D
(i), (ii) and (iv)
Option D ((i), (ii) and (iv)) is correct because statements (i), (ii), and (iv) accurately describe the filling of electron orbitals in the second, third, and fifth periods, respectively. Statement (iii) is incorrect.
20 Hard
20 of 492
Understanding +4 | -1
Statement I: Electrons are negatively charged.

Statement II: The application of electric and magnetic field deflected the rays in the discharge tube towards the positive plate.
View answer and explanation
Correct option: A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.
Option A is correct. Electrons are negatively charged, and their deflection towards the positive plate in a discharge tube confirms this negative charge.
21 Easy
21 of 492
Analyzing +4 | -1
Kinetic energy of an electron in hydrogen atom increases after transition from an orbit n1n_1 to another orbit n2n_2. Then
View answer and explanation
Correct option: B
nl>n2n_l>n_2
Option B (nl>n2n_l>n_2) is correct because the kinetic energy of an electron increases as it transitions to a lower energy level (closer to the nucleus).
22 Easy
22 of 492
Understanding +4 | -1
The Heisenberg^' s uncertainty principle can be applied to:
View answer and explanation
Correct option: D
An electron
Option D (An electron) is correct because Heisenberg's uncertainty principle is most significant for particles with very small mass, like electrons.
23 Medium
23 of 492
Analyzing +4 | -1
How many moles of He\mathrm{He} are produced when one mole of 92U238{ }_{92} \mathrm{U}^{238} disintegrates into 82 Pb206{ }_{82} \mathrm{~Pb}^{206}?
View answer and explanation
Correct option: C
8
Option A is correct because the decay of one Uranium-238 atom to Lead-206 involves the emission of 8 alpha particles, each of which is a Helium nucleus.
24 Easy
24 of 492
Remembering +4 | -1
Positive charge in an atom is:
View answer and explanation
Correct option: B
Concentrated in the nucleus
Option B is correct because the positive charge in an atom is concentrated in the nucleus due to the presence of protons.
25 Easy
25 of 492
Understanding +4 | -1
The nodes present in 3p-orbitals are
View answer and explanation
Correct option: A
One spherical, one planar
Option A (One spherical, one planar) is correct because a 3p-orbital has one radial node (spherical) and one angular node (planar).
26 Medium
26 of 492
Understanding +4 | -1
Which of the following conclusions could not be derived from Rutherford’s α\alpha - particle scattering experiment
View answer and explanation
Correct option: C
Electrons move in a circular path of fixed energy called orbits
Option C is correct because Rutherford's experiment focused on the nucleus and did not provide information about electron orbits.
27 Easy
27 of 492
Understanding +4 | -1
Visible spectrum of hydrogen shows that it exists in two different forms which are based on direction of spin of the:
View answer and explanation
Correct option: B
Nuclei of hydrogen atoms
Option B (Nuclei of hydrogen atoms) is correct because the two forms of hydrogen are based on the spin of the nuclei (ortho and para hydrogen).
28 Easy
28 of 492
Analyzing +4 | -1
Assertion : 1122Na{ }_{11}^{22} {Na} emits a position giving 1222Mg{ }_{12}^{22} {Mg}.

Reason : In β+\beta^{+}emission neutron is transformed into proton.
View answer and explanation
Correct option: D
If the assertion and reason both are false.
Option D (If the assertion and reason both are false) is correct because in β+\beta^+ emission, a proton is transformed into a neutron, and the atomic number decreases, not increases as suggested by the assertion.
29 Easy
29 of 492
Application +4 | -1
The number of s-electrons present in an ion with 55
protons in its unipositive state is
View answer and explanation
Correct option: A
10
Option A (10) is correct because an element with 55 protons in its unipositive state has 54 electrons, and the number of s-electrons can be determined from the electronic configuration.
30 Hard
30 of 492
Remembering +4 | -1
The emission spectrum of hydrogen is found to satisfy the expression for the energy change, ∆E (in joules), such that ΔE=2.18×10−18[1n12−1n22]\Delta E = 2.18 \times {10^{ - 18}}\left[ {\frac{1}{{n_1^2}} - \frac{1}{{n_2^2}}} \right] J, where, n1=1,2,3,  …{n_1} = 1,2,3,\; \ldots and n2=2,3,4,…{n_2} = 2,3,4, \ldots The spectral lines correspond to Paschen series are
View answer and explanation
Correct option: C
n1=3{n_1} = 3 and n2=4,5,6{n_2} = 4,5,6
Option C (n1=3{n_1} = 3 and n2=4,5,6{n_2} = 4,5,6) is correct because the Paschen series corresponds to transitions where the electron falls to the n=3 energy level.
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